INSTANT DOWNLOAD COMPLETE TEST BANK WITH ANSWERS
College Algebra 8th Edition by Ziegler, Byleen Barnett -Test Bank
Sample Questions
Chapter 5
- Evaluate to four significant digits.
Ans: 22.27
Section: 5.1
- Evaluate e9 – e–9 to four significant digits.
- A) 8103 B) 8107 C) 8111 D) 8115
Ans: A Section: 5.1
- Simplify.
(47x)10y
Ans: 470xy
Section: 5.1
- Graph y = 4ex.
Ans:
Section: 5.1
- Graph y = 5e–x.
- A) C)
- B) D)
Ans: B Section: 5.1
- Find the equations of any horizontal asymptotes without graphing.
y = + 8
- A) y = 0 B) y = 8 C) y = –8 D) No horizontal asymptote
Ans: D Section: 5.1
- Find the equations of any horizontal asymptotes without graphing.
y = ex – 7
Ans: y = –7
Section: 5.1
- Graph y = ex – 3.
Ans:
Section: 5.1
- Graph y = ex – 2.
- A) C)
- B) D)
Ans: D Section: 5.1
- Solve.
56x = 52x + 8
Ans: 2
Section: 5.1
- Solve.
- A) 3 B) 4 C) 5 D) –4
Ans: C Section: 5.1
- Solve.
= 1000
Ans:
Section: 5.1
- Solve.
x2ex + 4xex = 0
- A) 0 B) –4 C) 0, 4 D) 0, –4
Ans: D Section: 5.1
- Solve the exponential equation.
100x – 3 = 1000x
Ans: –6
Section: 5.1
- Graph .
Ans:
Section: 5.1
- Graph .
Ans:
Section: 5.1
- Graph f(x) = ex + 2 – 3.
Ans:
Section: 5.1
- Simplify.
- A) B) C) D)
Ans: D Section: 5.1
- Simplify.
- A) 0 B) C) D)
Ans: C Section: 5.1
- If you invest $4,500 in an account paying 2% compounded continuously, how much money will be in the account at the end of 4 years?
- A) $4,874.79 B) $4,879.93 C) $4,884.77 D) $4,888.11
Ans: A Section: 5.1
- If you invest $4,500 in an account paying 9.86% compounded continuously, how much money will be in the account at the end of 8 years? Round your answer to the nearest cent.
Ans: $9,903.39
Section: 5.1
- If $5,000 is deposited into an account earning 8% compounded weekly, and, at the same time, $7,000 is deposited into an account earning 6% compounded weekly, will the first account ever be worth more than the second? If so, when?
Ans: Yes, after 877 weeks
Section: 5.1
Use the following to answer questions 23-24:
The bacteria in a certain culture double every 7.9 hours. The culture has 2,000 bacteria at the start.
- Write an equation that gives the number of bacteria A in the culture after t hours.
Ans: A = 3,000(2t/7.8)
Section: 5.2
- How many bacteria will the culture contain after 4 hours?
- A) 3,306 bacteria B) 3,409 bacteria C) 3,508 bacteria D) 3,628 bacteria
Ans: B Section: 5.2
Use the following to answer questions 25-26:
A certain geographic region has a population of about 42,000,000 and a doubling time of 32 years. Assume that the growth continues at the same rate.
- Find the population in 5 years to two significant digits.
Ans: 57,000,000 people
Section: 5.2
- Find the population in 16 years to two significant digits.
- A) 30,000,000 people C) 32,000,000 people
- B) 31,000,000 people D) 33,000,000 people
Ans: D Section: 5.2
Use the following to answer questions 27-28:
The radioactive element americium-241 has a half-life of 432 years. Suppose we start with a 20-g mass of americium-241.
- How much will be left after 377 years? Compute the answer to three significant digits.
- A) 9 g B) 12.0 g C) 13.2 g D) 13.8 g
Ans: A Section: 5.2
- How much will be left after 486 years? Compute the answer to three significant digits.
Ans: 9.17 g
Section: 5.2
- The population of a certain geographic region is approximately 111 million and grows continuously at a relative growth rate of 1.17%. What will the population be in 8 years? Compute the answer to three significant digits.
- A) 121 million people C) 123 million people
- B) 122 million people D) 124 million people
Ans: B Section: 5.2
- The nuclear energy source on a certain space vehicle has a power output of P watts after t days as given by
P = 70e–0.0025t.
Graph this function for 0 ≤ t ≤ 100.
Ans:
Section: 5.2
- In a certain marine zone, the intensity I of light d feet below the surface is given approximately by
I = I0e–0.028d
where I0 is the intensity of light at the surface. To the nearest percent, what percentage of the surface light will reach a depth of 15 feet?
Ans: 66%
Section: 5.2
Use the following to answer questions 32-34:
An employee is hired to assemble toys. The learning curve
gives the number of toys the average employee is able to assemble per day after t days on the job.
- How many toys can the average employee assemble per day after 6 days of training? Round to the nearest integer.
- A) 24 toys B) 25 toys C) 26 toys D) 27 toys
Ans: B Section: 5.2
- How many toys can the average employee assemble per day after 13 days of training? Round to the nearest integer.
Ans: 44 toys
Section: 5.2
- Does N approach a limiting value as t increases without bound? Explain.
Ans: Yes, N approaches 60 as t increases without bound. This is the upper limit for the number of toys an employee can assemble per day.
Section: 5.2
Use the following to answer questions 35-36:
Radioactive Studies
Time in Hours
x |
Grams of Material
y |
0.1 | 2 |
1 | 1.2 |
2 | 0.6 |
3 | 0.3 |
4 | 0.2 |
5 | 0.1 |
6 | 0.06 |
- Find an exponential regression model of the form y = abx for the data set.
Ans: y = 2.0629(0.5495)x
Section: 5.2
- Estimate the amount of material remaining after 7 hours. Round to four decimal places.
Ans: 0.0312 grams
Section: 5.2
Use the following to answer questions 37-39:
x | y |
0 | 8 |
10 | 20 |
20 | 54 |
30 | 104 |
40 | 191 |
50 | 359 |
60 | 412 |
70 | 429 |
- Find a logistic regression model for the data.
- A) C)
- B) D)
Ans: D Section: 5.2
- Use the model to find the approximate value of y when x = 55.
- A) 340 B) 360 C) 380 D) 400
Ans: C Section: 5.2
- Using the model, what is the projected value of y when x = 70? Why does this differ from the value in the table?
Ans: 439; The model only approximates the data.
Section: 5.2
- Write in exponential form.
log 6 36 = 2
Ans: 36 = 62
Section: 5.3
- Write in exponential form.
log 10 0.0001 = –4
- A) 0001 = 10–4 C) 10 = (0.0001)–4
- B) 0001 = (–4)10 D) 10 = (–4)0.0001
Ans: A Section: 5.3
- Write in exponential form:
Ans: = 5–2
Section: 5.3
- Write in exponential form.
Ans: = 16–1/2
Section: 5.3
- Write in logarithmic form.
243 = 35
- A) log 3 5 = 243 B) log 5 3 = 243 C) log 3 243 = 5 D) log 243 3 = 5
Ans: C Section: 5.3
- Write in logarithmic form.
64 = 43
Ans: log 4 64 = 3
Section: 5.3
- Write in logarithmic form.
= 25–3/2
Ans:
Section: 5.3
- Write in logarithmic form.
= 4–2
Ans:
Section: 5.3
- Simplify.
log 4 1
- A) 0 B) 1 C) 4 D) 16
Ans: A Section: 5.3
- Simplify.
log 16 16
Ans: 1
Section: 5.3
- Simplify.
log 3 3
- A) 0 B) 1 C) 3 D) 9
Ans: B Section: 5.3
- Simplify.
log 2 27
- A) 0 B) 1 C) 2 D) 7
Ans: D Section: 5.3
- Simplify.
log 4 16
Ans: 2
Section: 5.3
- Simplify.
log 3 9
- A) B) C) 2 D) –2
Ans: C Section: 5.3
- Simplify.
log 2
- A) B) C) 5 D) –5
Ans: D Section: 5.3
- Simplify.
- A) 0 B) 1 C) 4 D) 7
Ans: D Section: 5.3
- Use a calculator to find log 20,630. Round your answer to four decimal places.
Ans: 4.3145
Section: 5.3
- Use a calculator to find Round your answer to four decimal places.
- A) 6144 B) 3.6357 C) 3.7479 D) 3.7661
Ans: A Section: 5.3
- Use a calculator to find . Round your answer to four decimal places.
Ans: 5.3471
Section: 5.3
- Use a calculator to find log 5 57. Round your answer to four decimal places.
- A) 3611 B) 2.5001 C) 2.5121 D) 2.8251
Ans: C Section: 5.3
- Use a calculator to find log 4 148.79. Round your answer to four decimal places.
Ans: 3.6086
Section: 5.3
- Evaluate x to four significant digits.
log x = 0.139
Ans: 1.377
Section: 5.3
- Evaluate x to four significant digits.
ln x = –1.445
- A) 2357 B) 0.2711 C) 0.3589 D) 0.4513
Ans: A Section: 5.3
- Solve.
log 3 x = 2
Ans: 9
Section: 5.3
- Solve.
log b 81 = 2
Ans: 9
Section: 5.3
- Solve.
log 16 32 = x
- A) B) C) 2 D)
Ans: B Section: 5.3
- Evaluate to three decimal places.
Ans: 0.858
Section: 5.3
- Use the properties of logarithms to write the expression in terms of and
Ans: log x + 7log y
Section: 5.3
- Use the properties of logarithms to write the expression as a single log.
log b x + 6 log b y
Ans:
Section: 5.3
- Use the properties of logarithms to write the expression as a single log.
–7ln(x + 1) + 6ln(x)
Ans:
Section: 5.3
- Given that and find
- A) B) –1 C) D)
Ans: B Section: 5.3
- Given that and find .
- A) 180 B) 4,500 C) 27 D) 161
Ans: C Section: 5.3
- Graph the logarithmic function.
f(x) = log 3 x + 2
Ans:
Section: 5.3
- Graph the logarithmic function.
f(x) = log 3 (x – 1)
- A)
- B)
- C)
- D)
Ans: B Section: 5.3
- Graph the logarithmic function.
f(x) = –log 3(x + 2)
Ans:
Section: 5.3
- Graph the logarithmic function.
f(x) = –ln(x + 1)
Ans:
Section: 5.3
- Find f –1 if f(x) = log 8 x.
Ans: f –1(x) = 8x
Section: 5.3
- Find f –1 if f(x) = 2log 8 (x – 3).
- A) f –1(x) = 82x – 3 C) f –1(x) = 8x/2 – 3
- B) f –1(x) = 82x + 3 D) f –1(x) = 8x/2 + 3
Ans: D Section: 5.3
- Find f –1 if f(x) = 6 – 3 log(x + 2).
Ans: f –1(x) = 100(10-x/3) – 2
Section: 5.3
The decibel level D of a sound is defined as
where I is the intensity of the sound measured in watts per square meter, and I0 is the intensity of the least audible sound, standardized to be I0 = 10–12 watts per square meter.
- A rock concert has a volume with an intensity of I = 1.0 ´ 10–1 W/m2. Find its rating in decibels.
Ans: 110 dB
Section: 5.4
- A radio is playing at a volume with an intensity of I = 5.6 ´ 10–6 W/m2. Find its rating in decibels to two significant digits.
- A) 77 dB B) 67 dB C) 60 dB D) 56 dB
Ans: B Section: 5.4
The magnitude on the Richter scale of an earthquake is given by the equation
where E is the energy released by the earthquake, measured in joules, and E0 is the energy released by a very small reference earthquake, standardized at E0 = 104.40 joules.
- An earthquake has an energy release of 4.93 ´ 108 joules. What was its magnitude on the Richter scale?
- A) 6 B) 2.7 C) 2.8 D) 2.9
Ans: D Section: 5.4
- If one earthquake measures 5.2 on the Richter scale, and another measures 6.2, how many times more powerful was the 6.2 earthquake? Round to the nearest whole number.
Ans: 32 times as powerful
Section: 5.4
The velocity v of a rocket at burnout (depletion of fuel supply) is given by
where c is the exhaust velocity of the rocket engine, Wt is the takeoff weight (fuel, structure, and payload), and Wb is the burnout weight (structure and payload).
- A rocket has a weight ratio Wt/Wb = 18.2 and an exhaust velocity c = 2.34 kilometers per second. What is its velocity at burnout? Compute the answer to two decimal places.
- A) 06 km/s B) 6.44 km/s C) 6.79 km/s D) 7.20 km/s
Ans: C Section: 5.4
- A rocket has a weight ratio Wt/Wb = 7.6 and an exhaust velocity c = 6.8 kilometers per second. What is its velocity at burnout? Compute the answer to two decimal places.
Ans: 13.79 km/s
Section: 5.4
The pHH scale is defined as
pH = –log[H+]
where [H+] is the hydrogen ion concentration, in moles per liter. Substances with a pH less than 7 are acidic, and those with a pH greater than 7 are basic.
Use the following to answer questions 85-86:
A solution has a hydrogen ion concentration of [H+] = 9.5 ´ 10–8.
- Find the pH of the solution. Round your answer to one decimal place.
- A) 3 B) 8.4 C) 8.5 D) 8.6
Ans: B Section: 5.4
- Is the solution acidic or basic?
- A) Acidic B) Basic
Ans: B Section: 5.4
Use the following to answer questions 87-88:
A solution has a hydrogen ion concentration of [H+] = 9.5 ´ 10–3.
- Find the pH of the solution. Round your answer to one decimal place.
Ans: 4.1
Section: 5.4
- Is the solution acidic or basic?
- A) Acidic B) Basic
Ans: A Section: 5.4
Use the following to answer questions 89-91:
The following table shows the number of pounds a person lost since beginning a diet.
Time
(days) |
Pounds Lost |
7 | 2 |
14 | 12 |
21 | 17 |
28 | 20 |
35 | 22.5 |
42 | 24 |
49 | 25 |
56 | 25.5 |
- Find a logarithmic regression model for the data.
- A) y = –18.739 + 11.383 ln x C) y = –13.235 + 14.128 ln x
- B) y = –15.381 + 12.590 ln x D) y = –10.546 + 13.533 ln x
Ans: A Section: 5.4
- Use the regression model to estimate the person’s total weight loss after 54 days.
- A) 3 pounds B) 25.5 pounds C) 26.7 pounds D) 28.1 pounds
Ans: C Section: 5.4
- According to the regression model, what is the projected weight loss for 97 days?
- A) 3 pounds B) 35.6 pounds C) 37.2 pounds D) 37.8 pounds
Ans: A Section: 5.4
- Solve. Round your answer to three decimal places.
10x = 32.8
- A) 516 B) 3.28 C) 3.490 D) 328
Ans: A Section: 5.5
- Solve. Round your answer to three decimal places.
e3x – 2 + 30 = 180
Ans: 2.337
Section: 5.5
- Solve. Round your answer to three decimal places.
10–x 10 4 = 0.603
Ans: 4.220
Section: 5.5
- Solve exactly.
log(3x – 5) = 2
- A) B) C) 35 D) 34
Ans: C Section: 5.5
- Solve exactly.
log 20 + log x = 3
Ans: 50
Section: 5.5
- Solve exactly.
log (x + 4) – log (x – 3) = log 8
Ans: 4
Section: 5.5
- Solve. Round your answer to three decimal places.
30 = 1.09x
- A) 467 B) 27.523 C) 3.401 D) 13.268
Ans: A Section: 5.5
- Solve. Round your answer to three decimal places.
e–3.7x + 35 = 0
- A) –0.961 B) 961 C) 9.459 D) No solution
Ans: D Section: 5.5
- Solve. Round your answer to three decimal places.
157 = 768e–0.58x
- A) 737 B) 0.352 C) –0.352 D) No solution
Ans: A Section: 5.5
- Solve exactly.
ln(7x + 2) = ln(5x + 14)
Ans: 6
Section: 5.5
- Solve exactly.
log(x + 20) – log(x + 2) = log x
- A) –5, 4 B) 4 C) 5 D) No solution
Ans: B Section: 5.5
- Solve exactly.
(ln x)3 = ln x9
Ans: 1, e3, e–3
Section: 5.5
- Solve exactly.
9log x = 9x
- A) B) C) D)
Ans: B Section: 5.5
- If $7,000 is placed in an account with an annual interest rate of 3%, how long will it take the amount to double if the interest is compounded annually? Round your answer to two decimal places.
Ans: 23.45 years
Section: 5.5
- If $4,000 is placed in an account with an annual interest rate of 5%, how long will it take the amount to triple if the interest is compounded annually? Round your answer to two decimal places.
- A) 52 years B) 22.92 years C) 23.32 years D) 23.72 years
Ans: A Section: 5.5
- What annual interest rate will ensure that $6,500 will grow to $9,000 if it is invested for 6 years with interest compounded continuously? Round your answer to two decimal places.
Ans: 5.42%
Section: 5.5
- How many years will it take $3,500 to grow to $8,684 if it is invested at an annual rate of 2%, compounded continuously? Round your answer to one decimal place.
- A) 4 years B) 44.9 years C) 45.4 years D) 45.9 years
Ans: C Section: 5.5
- A mathematical model for population growth is given by P = P0ert where P is the population after t years, P0 is the population at t = 0, and the population is assumed to grow continuously at the annual rate r. How long would it take a population to triple if the growth rate were 2.4%? Round to one decimal place.
- A) 8 years B) 46.3 years C) 46.8 years D) 47.3 years
Ans: A Section: 5.5